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C 400 − 216 − 801 cap C to the 400th power minus 216 minus 801
𝐶 4 0 0 − 2 1 6 − 8 0 1
Algebra
Trigonometry
Calculus
  1. ⬚ ⬚ placeholder raised to the placeholder power
    ⬚ ⬚
    ⬚ ⬚ the placeholder root of placeholder end-root
    ⬚ ⬚ √
    < is less than
    <
    (
    )
    AC
    ⬚ ⬚ the fraction with numerator placeholder and denominator placeholder end-fraction
    ⬚ ⬚
    | ⬚ | the absolute value of placeholder end-absolute-value
    | ⬚ |
    ≤ is less than or equal to
    ≤
    7
    8
    9
    ÷
    log ⬚ log base placeholder of
    l o g ⬚
    ⬚ ! placeholder exclamation mark
    ⬚ !
    > is greater than
    >
    4
    5
    6
    ×
    i i
    𝑖
    % %
    %
    ≥ is greater than or equal to
    ≥
    1
    2
    3
    −
    x x
    𝑥
    y y
    𝑦
    = equals
    =
    0
    .
    +
  2. sin sine
    s i n
    cos cosine
    c o s
    tan tangent
    t a n
    (
    )
    AC
    csc cosecant
    c s c
    sec secant
    s e c
    cot cotangent
    c o t
    7
    8
    9
    ÷
    arcsin arc sine
    a r c s i n
    arccos arc cosine
    a r c c o s
    arctan arc tangent
    a r c t a n
    4
    5
    6
    ×
    ⬚ 2 placeholder squared
    ⬚ 2
    ⬚ ° placeholder degrees
    ⬚ °
    π pi
    𝜋
    1
    2
    3
    −
    x x
    𝑥
    y y
    𝑦
    = equals
    =
    0
    .
    +
  3. d d ⬚ the fraction with numerator d and denominator d placeholder end-fraction
    𝑑 𝑑 ⬚
    ∞ infinity
    ∞
    ⬚ ⬚ the placeholder root of placeholder end-root
    ⬚ ⬚ √
    (
    )
    AC
    lim ⬚ → ⬚ limit over placeholder right arrow placeholder of
    l i m ⬚ → ⬚
    lim ⬚ → ⬚ + limit over placeholder right arrow placeholder raised to the positive power of
    l i m ⬚ → ⬚ +
    lim ⬚ → ⬚ − limit over placeholder right arrow placeholder raised to the negative power of
    l i m ⬚ → ⬚ −
    7
    8
    9
    ÷
    log ⬚ log base placeholder of
    l o g ⬚
    C ( n , k ) cap C open paren n comma k close paren
    𝐶 ( 𝑛 , 𝑘 )
    P ( n , k ) cap P open paren n comma k close paren
    𝑃 ( 𝑛 , 𝑘 )
    4
    5
    6
    ×
    ∑ sum of
    ∫ ⬚ integral of placeholder
    ⬚
    ∫ ⬚ ⬚ ⬚ integral from placeholder to placeholder of placeholder
    ⬚ ⬚ ⬚
    1
    2
    3
    −
    x x
    𝑥
    y y
    𝑦
    e e
    𝑒
    0
    .
    +
Simplify the expression
Simplify the expression
Solution
C 400 − 1017 cap C to the 400th power minus 1017
𝐶 4 0 0 − 1 0 1 7
Step
C 400 − 216 − 801 modified cap C to the 400th power minus 216 minus 801 with boxed outline
𝐶 4 0 0 − 2 1 6 − 8 0 1
Calculate the difference
C 400 − 1017 cap C to the 400th power minus modified 1017 with boxed outline
𝐶 4 0 0 − 1 0 1 7
Solution
C 400 − 1017 cap C to the 400th power minus 1017
𝐶 4 0 0 − 1 0 1 7
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